Skip to main content
CALCFORGE
Problems
Dashboard
Leaderboard
Classroom
Pricing
Log in
Sign up free
CALCFORGE
Log in
Sign up free
Home
/
Problems
/
Calculus
/
Applications
/
Time to Maximum Height
medium
Difficulty: medium
f(x) Applications
·
18 pts
·
0 solved
Time to Maximum Height
Problem Statement
A projectile’s height is
h
(
t
)
=
−
16
t
2
+
64
t
+
5
ft. Find the time (s) of maximum height.
\text{A projectile's height is } h(t) = -16t^2 + 64t + 5 \text{ ft. Find the time (s) of maximum height.}
A projectile’s height is
h
(
t
)
=
−
16
t
2
+
64
t
+
5
ft. Find the time (s) of maximum height.
Your Answer (variable: x)
Live LaTeX preview appears here as you type…
Log in to submit
Guest mode: browsing only. Log in to submit and track progress.
Power-Ups
Skip
Super Hint
Graph Overlay
Hints
Reveal hint 1 of 2 (−2 XP)
Show step-by-step solution
Discussion (0)
Post
Loading discussion…
f(x)
Tips
Use standard math syntax:
^
for powers,
*
for multiplication.
Functions: sin, cos, tan, exp, log (natural log), sqrt.
Constants: pi, e.
For antiderivatives you can omit "+ C".